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The sum of the squares of three numbers is 138, while the sum of their products taken two at a time is 131. Their sum is:

20
30
40
None of these
Explanation:

Let the three numbers be a, b and c.

According to the given condition

=>$ a^2 + b^2 + c^2 $= 138.

ANd, ab + bc + ca = 131.

Now, we know that $(a+b+c) ^2$ =$a^2 + b^2 + c^2$ + 2(ab+bc+ca)

On taking values we get$ (a+b+c) ^2$ = 138 + 2(131) = 400

=> a + b + c = 20.

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