Let the Cost price of 1 article be Re.1.
Therefore, Cost price of 20 articles = Rs. 20.
Selling price of 16 articles = Rs. 20
Therefore, Selling price of 20 articles = (20/16) * 20 = 25
Profit = Selling price - Cost price
= 25 - 20 = 5
Percentage of profit = Profit / Cost price * 100.
= 5 / 20 * 100 = 25% Profit
Price at which he brought the chocolates; price per chocolate = Rs. 10/8 = Rs. 1.25
Price at which he sold the chocolate; price per chocolate = Rs 8/10 = Rs .0.80
% profit or loss =[(0.8 - 1.25) / 1.25] x 100 = -(0.45/1.25) x 100 = -36 %
Therefore, % loss = 36 %
Let the present ages (in years) of A and B be 6x and 5x respectively.
Given: 6x + 5x = 44 => x = 4
Therefore, the ratio of ages after 8 years will be 6x + 8 : 5x + 8 or 8 : 7
Let Sumith’s age one year ago be 4x years and Akhil’s age be 3x years.
The present age of Sumith = (4x + 1) years
The present age of Akhil = (3x + 1) years
One year hence, Sumith’s age = (4x + 2) years and Akhil’s age = (3x + 2) years.
According to the question,
(4x + 2)/(3x + 2) = 5/4 => 16x + 8 = 15x +10
or x = 2
Therefore, the sum of their present ages = 4x + 1 + 3x + 1 = 7x + 2
= 7 x 2 + 2 = 16 years.
Consider that there are a total of 24 units of work to be done (LCM of 6 and 8). Also, Phani can finish P units of work per day and Rani can finish R units of work per day.
Working together, they can complete 24 units in 6 days. Hence, in one day, they can finish 4 units of work.
P + R = 4 ------- (i)
Rani alone can finish 24 units of work in 8 days. Hence, in one day, she can finish 3 units of work.
R = 3.
Substituting in eq (i), P = 1.
At the rate of 1 unit per day, it will take Phani 24 days to complete the given work.
As the given sum is for 21 days or 28 days of wages of X or Y, the sum will be completely divisible by 21 and 28. So, let the sum be LCM of 21 and 28 = 84.
X gets 84/21= ₨. 4/day
Y gets 84/28= Rs. 3/day
Therefore, (X + Y) together gets Rs. 7/day
Thus, Rs 84 is sufficient for 84/7 = 12 days to pay both of them
Given: 3 men = 5 women
Therefore, 5 men = 25 / 3 women
Now, 5 men + 6 women = 25 / 3 + 6 = 43/3 women.
5 women can reap in 43 days.
.’. 43/3 women can reap in X days.
:43 x 5 = (43 / 3)X (W1D1=W2D2)
X = 15 days.
In half an hour, he covers half of the distance, i.e., AC.
The speed was 8 kmph throughout the journey of half an hour.
Hence, he must have travelled 4 kilometers.
Since he traveled along the sides of a square field, each side of the square field measured 2 kilometers.
Therefore, area of the square = 2 x 2 = 4 sq kms.
Let X kmph be the speed of the train.
The relative speed of the train and the man is (x - 6). Using the relation Speed = Distance / Time,
=> (X - 6) x 5/18 x 5 = 100
X = 78 kmph
Let the speed of the car be Y kmph.
=> (78 - Y) x 5/18 x 6 = 100
=> Y = 18
The average speed of the first man = 32 kmph.
Time taken to complete the journey = 192/32 = 6h.
The second man leaves 2 1/2 hours late and reaches half an hour earlier than the first man. Hence, the second man’s journey lasted for 6 - 2 1/2 - 1/ 2 = 3h.
Therefore, the speed of the second man = 192/3=64 kmph.
Hence, the required ratio = 32 : 64 or 1 : 2.