This is a simple multiplication.
333 times 135 = 333 × 135 = 44955
49/10 + 3/11 + 7/15
=$\dfrac{1617+90+154}{330}$=$\dfrac{1861}{330}$
1/4th of 1/2 of 3/4th of 52000 =1/4×1/2×3/4×52000=4875
57/67×32/171×45/128=$\dfrac{57×32×45}{ 67×171×128}$=15/268
283 × 56 + 252 = 20 × ?
⇒ 15848 + 252 = 20x
⇒ x = 805
(5863 - √2704) × 0.5 = x
⇒ (5863 – 52) × 0.5 = x
⇒ x = 2905.5
We have total capacity as g litres.
a liter was removed
So Fraction of the full tank that is removed = a/g
Given expression is-
76% of 1285 = 35% of 1256 +?
⇒ (76/100) × 1285 = (35/100) × 1256 +?
⇒ 97660/100 = 43960/100 +?
⇒ ? = (97660/100) – (43960/100)
⇒ ? = 53700/100 = 537
We are given a 5 digit number
Let first digit be 'X'
then 5th digit is '3X'
let 2nd digit be 'Y'
then 3rd digit is 'Y - 3'
and 4th digit is 'Y + 4'
then the no is '(X)(Y)(Y - 3)(Y + 4)(3X)'
from the above we can say 3X <= 9
so X<=3 and any of the digit in the number is <= 9
and also given that 3 pairs sum is 11...
Also Y–3 ≥ 0 and Y+4 ≤ 9
⇒ Y ≥ 3 and Y ≤ 5 i.e. Y = 3,4 or 5
for x = 1, all the conditions won’t be satisfied.
For x = 2,
Let Y = 5
∴ The number is 25296
Let’s find a number which is completely divisible by 4, 6, 8, 12 and 16.
To find such number, we need to find the LCM of all these numbers
LCM of (4,6) , 8 , 12 , 16
= 12 , 8 , 12 , 16
= LCM of (12 , 8) , LCM of (12 , 16)
= 24 , 48
= LCM of (24 , 48)
= 48
Hence 48 + 2 ie 50 will leave a remainder of 2 if divided by any of the following numbers : 4, 6, 8, 12 and 16