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Aptitude Problems on Ages Test yourself

2898.The age of father 10 years ago was thrice the age of his son. Ten years hence, fathers age will be twice that of his son. The ratio of their present ages is:
5 : 2
7 : 3
9 : 2
13 : 4
Explanation:

Let the ages of father and son 10 years ago be 3$ x $ and $ x $ years respectively.

Then, $\left(3x + 10\right)$ + 10 = 2[$\left( x + 10\right)$ + 10]

$\Rightarrow$ 3$ x $ + 20 = 2$ x $ + 40

$\Rightarrow x $ = 20.

$\therefore$ Required ratio = $\left(3x + 10\right)$ : $\left(x + 10\right)$ = 70 : 30 = 7 : 3.

2899.Present ages of Kiran and Syam are in the ratio of 5 : 4 respectively. Three years hence, the ratio of their ages will become 11 : 9 respectively. What is Syams present age in years?
28
27
26
24
Explanation:

Ratio of the present age of Kiran and Syam = 5 : 4

Let the present age of Kiran = 5$x$

Present age of Syam = 4$x$

After 3 years, ratio of their ages = 11:9

=> $\left(5x + 3\right)$ : $\left(4x + 3\right)$ = 11 : 9

=> 9$\left(5x + 3\right)$ = 11$\left(4x + 3\right)$

=> 45$x$ + 27 = 44$x$ + 33

=> $x$ = 33-27 =6

Syams present age = 4$x$ = $(4 \times 6)$ = 24

2900.A mans age is 125% of what it was 10 years ago, but $83\dfrac{1}{3}$% of what it will be after 10 years. What is his present age?
70
60
50
40
Explanation:

Let the age before 10 years = $x$

Then $\dfrac{125x}{100}$ = $x$ + 10

=>125$x$ = 100$x$ + 1000

=> $x$ = $\dfrac{1000}{25}$= 40

Present age = $x$ + 10 = 40 +10 = 50

2901.Sachin is younger than Rahul by 7 years. If their ages are in the respective ratio of 7 : 9, how old is Sachin?
16 years
18 years
28 years
24.5 years
Explanation:

Let Rahuls age be $ x $ years.

Then, Sachins age = $\left(x - 7\right)$ years.

$\therefore \dfrac{x - 7}{x} $=$ \dfrac{7}{9} $

$\Rightarrow$ 9$ x $ - 63 = 7$ x $

$\Rightarrow$ 2$ x $ = 63

$\Rightarrow x $ = 31.5

Hence, Sachins age =$\left(x - 7\right)$ = 24.5 years.

2902.A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, the how old is B?
7
8
9
10
Explanation:

Let Cs age be $ x $ years. Then, Bs age = 2$ x $ years. As age = $\left(2x + 2\right)$ years.

$\therefore$ $\left(2x + 2\right)$ + 2$ x $ + $ x $ = 27

$\Rightarrow$ 5$ x $ = 25

$\Rightarrow x $ = 5.

Hence, Bs age = 2$ x $ = 10 years.

44311. What is John’s present age, if after 10 years his age will be 5 times his age 5 years back.
6.2years
7.7years
8.7years
10years
Explanation:

Let John’s present age be x
John’s age before 5 years = (x - 5)
John’s age after 10 years = (x + 10)
We are given that, John’s age after 10 years (x + 10) is 5 times his age 5 years back (x – 5)
Therefore, (x + 10) = 5 (x – 5)
Solving the equation, we get
x + 10 = 5x – 25
4x = 35
x = 8.75 years

44373. Father is four times the age of his daughter. If after 5 years, he would be threee times of daughter’s age, then further after 5 years, how many times he would be of his daughter’s age?
1.5 times
2 times
2.5 times
3 times
Explanation:

Let the daughter's age be x and father's age be 4x.
So as per question, 4x + 5 = 3(x + 5). So x = 10.
Hence present age of daughter is 10 years and present age of father is 40 years.
So after 5 + 5 = 10 years, daughter age would be 20 years and father’s age would be 50 years.
Hence father would be 50/20 = 2.5 times of daughter’s age.

44374.What is Aman's present age, if after 20 years his age will be 10 times his age 10 years back?
6.2 years
7.7 years
13.3 years
10 years
Explanation:

Let Aman's present age be x
Aman's age before 10 years = x - 10)
Aman's age after 20 years = (x + 20)
We are given that, Aman's age after 20 years (x + 20) is 10 times his age 10 years back (x – 10)
Therefore, (x + 20) = 10 (x – 10)
Solving the equation, we get x + 20 = 10x – 100
9x = 120, x = 13.3 years

44375.Nisha is 15 years elder to Romi. If 5 years ago, Nisha was 3 times as old as Romi, then find Nisha’s present age.
32.5 years
27.5 years
25 years
24.9 years
Explanation:

Let age of Romi be y
Nisha is 15 years elder than Romi = (y + 15). So Nisha's age 5 years ago = (y + 15 – 5).
Romi's age before 5 years = (y – 5) 5 years ago, Nisha is 3 times as old as Romi
(y + 15 – 5) = 3 (y – 5)
(y + 10) = (3y – 15)
2y = 25 ⇒ y = 12.5v Romi's age = 12.5 yearsv Nisha's age = (y + 15) = (12.5 + 15) = 27.5 years.

44376.One year ago, the ratio of Honey and Piyush ages was 2: 3 respectively. After five years from now, this ratio becomes 4: 5. How old is Piyush now?
5 years
25 years
10 years
15 years
Explanation:

We are given that age ratio of Honey: Piyush = 2: 3
Honey’s age = 2x and Piyush’s age = 3x
One year ago, their age was 2x and 3x.
Hence at present, Honey's age = 2x +1 and Piyush's age = 3x +1
After 5 years, Honey’s age = (2x +1) + 5 = (2x + 6)
Piyush's age = (3x +1) + 5 = (3x + 6)
After 5 years, this ratio becomes 4: 5.
Therefore, (2x+6) / (3x+6) = 4/5
10x + 30 = 12x + 24 ⇒ x = 3
Piyush's present age = (3x + 1) = (3x 3 + 1) = 10 years
Honey's present age = (2x + 1) = (2x 3 + 1) = 7 years

44377.Ten years ago, the age of mother was three times the age of her son. After ten years, mother’s age will be twice that of his son. Find the ratio of their present ages.
11 : 7
9 : 5
7 : 4
7 : 3
Explanation:

10 years ago, age of mother was three times the age of her son. Say, the age of son was x and mother's age was 3x.
At present: Mother's age is (3x + 10) and son’s age is (x + 10)
After ten years: Mother's age will be (3x + 10) +10 and son’s age will be (x + 10) + 10.
Given that, mother’s age is twice that of son after ten years.
(3x + 10) +10 = 2 [(x + 10) + 10]
(3x + 20) = 2[x + 20]
Solving the equation, we get x = 20
(3x + 10): (x + 10) = 70: 30 = 7: 3.

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