1333.Five bells begin to toll together and toll
respectively at intervals of 6,7,8,9 and 12 seconds.
How many times they will toll together
in one hour, excluding the one at the start?
respectively at intervals of 6,7,8,9 and 12 seconds.
How many times they will toll together
in one hour, excluding the one at the start?
6
7
5
2
Explanation:
L.C.M. of 6,7,8,9 and 12
= 2x2x3x7x2x3 = 504
ie, The bells will toll together after each 504
seconds. In one hour, they will toll together
(60*60)/504= 7 times
L.C.M. of 6,7,8,9 and 12
= 2x2x3x7x2x3 = 504
ie, The bells will toll together after each 504
seconds. In one hour, they will toll together
(60*60)/504= 7 times
1382.If 9 men working 6 hours a day can do a work in 88 days. Then 6 men
working 8 hours a day can do it in how many days?
working 8 hours a day can do it in how many days?
100days
58days
99days
90days
Explanation:
From the above formula i.e (m1*t1/w1) = (m2*t2/w2)
so (9*6*88/1) = (6*8*d/1)
on solving, d = 99 days.
From the above formula i.e (m1*t1/w1) = (m2*t2/w2)
so (9*6*88/1) = (6*8*d/1)
on solving, d = 99 days.
1383.If 34 men completed 2/5th of a work in 8 days working 9 hours a day.
How many more man should be engaged to finish the rest of the work in 6 days
working 9 hours a day?
How many more man should be engaged to finish the rest of the work in 6 days
working 9 hours a day?
100mens
102mens
112mens
120mens
Explanation:
From the above formula i.e (m1*t1/w1) = (m2*t2/w2)
so, (34*8*9/(2/5)) = (x*6*9/(3/5))
so, x = 136 men
number of men to be added to finish the work = 136-34 = 102 men
From the above formula i.e (m1*t1/w1) = (m2*t2/w2)
so, (34*8*9/(2/5)) = (x*6*9/(3/5))
so, x = 136 men
number of men to be added to finish the work = 136-34 = 102 men
1384.If 5 women or 8 girls can do a work in 84 days. In how many days can
10 women and 5 girls can do the same work?
10 women and 5 girls can do the same work?
30days
32days
35days
40days
Explanation:
Given that 5 women is equal to 8 girls to complete a work. So, 10 women =
16 girls. Therefore 10 women + 5 girls = 16 girls + 5 girls = 21 girls.
8 girls can do a work in 84 days then 21 girls can do a work in (8*84/21) = 32 days.
Therefore 10 women and 5 girls can a work in 32 days
Given that 5 women is equal to 8 girls to complete a work. So, 10 women =
16 girls. Therefore 10 women + 5 girls = 16 girls + 5 girls = 21 girls.
8 girls can do a work in 84 days then 21 girls can do a work in (8*84/21) = 32 days.
Therefore 10 women and 5 girls can a work in 32 days
1385.Worker A takes 8 hours to do a job. Worker B takes 10 hours to do the
same job. How long it take both A & B, working together but independently, to do
the same job?
same job. How long it take both A & B, working together but independently, to do
the same job?
40/9days
39/5days
51/9days
None of these
Explanation:
As one hour work = 1/8. Bs one hour work = 1/10. (A+B)s one hour work
= 1/8+1/10 = 9/40. Both A & B can finish the work in 40/9 days
As one hour work = 1/8. Bs one hour work = 1/10. (A+B)s one hour work
= 1/8+1/10 = 9/40. Both A & B can finish the work in 40/9 days
1386.A can finish a work in 18 days and B can do the same work in half the
time taken by A. Then,working together, what part of the same work they can finish
in a day?
time taken by A. Then,working together, what part of the same work they can finish
in a day?
A+B=1/6
A+B=5/6
A+B=1/4
A+B=2/3
Explanation:
Given that B alone can complete the same work in days = half the time
taken by A = 9 days
As one day work = 1/18
Bs one day work = 1/9
(A+B)s one day work = 1/18+1/9 = 1/6
Given that B alone can complete the same work in days = half the time
taken by A = 9 days
As one day work = 1/18
Bs one day work = 1/9
(A+B)s one day work = 1/18+1/9 = 1/6
1387.A is twice as good a workman as B and together they finish a piece of
work in 18 days.In how many days will A alone finish the work.
work in 18 days.In how many days will A alone finish the work.
21days
25days
22days
27days
Explanation:
if A takes x days to do a work then B takes 2x days to do the same work
= > 1/x+1/2x = 1/18
= > 3/2x = 1/18
= > x = 27 days.
Hence, A alone can finish the work in 27 days.
if A takes x days to do a work then B takes 2x days to do the same work
= > 1/x+1/2x = 1/18
= > 3/2x = 1/18
= > x = 27 days.
Hence, A alone can finish the work in 27 days.
1388.A can do a certain work in 12 days. B is 60% more efficient than A.
How many days does B alone take to do the same job?
How many days does B alone take to do the same job?
9/11days
11/7days
15/2days
13/5days
Explanation:
Ratio of time taken by A & B = 160:100 = 8:5
Suppose B alone takes x days to do the job.
Then, 8:5::12:x
= > 8x = 5*12
= > x = 15/2 days.
Ratio of time taken by A & B = 160:100 = 8:5
Suppose B alone takes x days to do the job.
Then, 8:5::12:x
= > 8x = 5*12
= > x = 15/2 days.
1389.A can do a piece of work n 7 days of 9 hours each and B alone can do it
in 6 days of 7 hours each. How long will they take to do it working together 8 2/5
hours a day?
in 6 days of 7 hours each. How long will they take to do it working together 8 2/5
hours a day?
2days
3days
4days
None of these
Explanation:
A can complete the work in (7*9) = 63 days
B can complete the work in (6*7) = 42 days
= > As one hours work = 1/63 and
Bs one hour work = 1/42
(A+B)s one hour work = 1/63+1/42 = 5/126
Therefore, Both can finish the work in 126/5 hours.
Number of days of 8 2/5 hours each = (126*5/(5*42)) = 3 days
A can complete the work in (7*9) = 63 days
B can complete the work in (6*7) = 42 days
= > As one hours work = 1/63 and
Bs one hour work = 1/42
(A+B)s one hour work = 1/63+1/42 = 5/126
Therefore, Both can finish the work in 126/5 hours.
Number of days of 8 2/5 hours each = (126*5/(5*42)) = 3 days
1390.A takes twice as much time as B or thrice as much time to finish a piece
of work. Working together they can finish the work in 2 days. B can do the work
alone in ?
of work. Working together they can finish the work in 2 days. B can do the work
alone in ?
3hours
6hours
4hours
8hours
Explanation:
Suppose A,B and C take x,x/2 and x/3 hours respectively finish the
work then 1/x+2/x+3/x = 1/2
= > 6/x = 1/2
= >x = 12
So, B takes 6 hours to finish the work.
Suppose A,B and C take x,x/2 and x/3 hours respectively finish the
work then 1/x+2/x+3/x = 1/2
= > 6/x = 1/2
= >x = 12
So, B takes 6 hours to finish the work.
1391.X can do ¼ of a work in 10 days, Y can do 40% of work in 40 days and
Z can do 1/3 of work in 13 days. Who will complete the work first?
Z can do 1/3 of work in 13 days. Who will complete the work first?
Z
X
Y
X,Y
Explanation:
Whole work will be done by X in 10*4 = 40 days.
Whole work will be done by Y in (40*100/40) = 100 days.
Whole work will be done by Z in (13*3) = 39 days
Therefore, Z will complete the work first.
Whole work will be done by X in 10*4 = 40 days.
Whole work will be done by Y in (40*100/40) = 100 days.
Whole work will be done by Z in (13*3) = 39 days
Therefore, Z will complete the work first.
1392.If A can complete a work in 10 days and B is 100 faster than A.
How much time B will take to complete the work?
How much time B will take to complete the work?
20days
21days
22days
30days
Explanation:
Men at work earlier = 10
Men at work later = 5
Ration of workers = a : b = 2 : 1
10 men can perform the complete task = 10 days
5 men will perform the same task in = b : a time = 1 : 2 => 20 days.
Men at work earlier = 10
Men at work later = 5
Ration of workers = a : b = 2 : 1
10 men can perform the complete task = 10 days
5 men will perform the same task in = b : a time = 1 : 2 => 20 days.
1393.A group of men completes a work in 10 days, but five of them are
absent and so the rest do the work in 12 days. Find the original number of Men.
absent and so the rest do the work in 12 days. Find the original number of Men.
26
28
30
32
Explanation:
More men, less days.
= Total men at work =30
More men, less days.
= Total men at work =30
1394.A can do a certain work in 12 days. B is 60% more efficient than A. How many
days does B alone take to do the same job?
days does B alone take to do the same job?
15/2days
12/7days
14/9days
None of these
Explanation:
Ratio of time taken by A & B = 160:100 = 8:5
Suppose B alone takes x days to do the job.
Then, 8:5::12:x
= > 8x = 5*12
= > x = 15/2 days.
Ratio of time taken by A & B = 160:100 = 8:5
Suppose B alone takes x days to do the job.
Then, 8:5::12:x
= > 8x = 5*12
= > x = 15/2 days.
1395.A can do a piece of work in 7 days of 9 hours each and B alone can do it in 6 days
of 7 hours each. How long will they take to do it working together 8 2/5 hours a day?
of 7 hours each. How long will they take to do it working together 8 2/5 hours a day?
2days
3days
5days
11days
Explanation:
A can complete the work in (7*9) = 63 days
B can complete the work in (6*7) = 42 days
= > As one hours work = 1/63 and
Bs one hour work = 1/42
(A+B)s one hour work = 1/63+1/42 = 5/126
Therefore, Both can finish the work in 126/5 hours.
Number of days of 8 2/5 hours each = (126*5/(5*42)) = 3 days
A can complete the work in (7*9) = 63 days
B can complete the work in (6*7) = 42 days
= > As one hours work = 1/63 and
Bs one hour work = 1/42
(A+B)s one hour work = 1/63+1/42 = 5/126
Therefore, Both can finish the work in 126/5 hours.
Number of days of 8 2/5 hours each = (126*5/(5*42)) = 3 days
1412.It was calculated that 75 men could complete a piece of work in 20 days.
When work was scheduled to commence, it was found necessary to send 25
men to another project. How much longer will it take to complete the work?
When work was scheduled to commence, it was found necessary to send 25
men to another project. How much longer will it take to complete the work?
30
33
15
20
Explanation:
Before:
One day work = 1 / 20
One mans one day work = 1 / ( 20 * 75)
Now:
No. Of workers = 50
One day work = 50 * 1 / ( 20 * 75)
The total no. of days required to complete the work = (75 * 20) / 50 =
30
Before:
One day work = 1 / 20
One mans one day work = 1 / ( 20 * 75)
Now:
No. Of workers = 50
One day work = 50 * 1 / ( 20 * 75)
The total no. of days required to complete the work = (75 * 20) / 50 =
30
1415.A man was engaged on a job for 30 days on the condition that he would get a
wage of Rs. 10 for the day he works, but he have to pay a fine of Rs. 2 for
each day of his absence. If he gets Rs. 216 at the end, he was absent for work
for ... days
wage of Rs. 10 for the day he works, but he have to pay a fine of Rs. 2 for
each day of his absence. If he gets Rs. 216 at the end, he was absent for work
for ... days
8 days
7 days
5 days
4 days
Explanation:
The equation portraying the given problem is:
10 * x – 2 * (30 – x) = 216 where x is the number of working days.
Solving this we get x = 23
Number of days he was absent was 7 (30-23) days.
The equation portraying the given problem is:
10 * x – 2 * (30 – x) = 216 where x is the number of working days.
Solving this we get x = 23
Number of days he was absent was 7 (30-23) days.
3203.If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be:
4 days
5 days
6 days
7 days
Explanation:
Let 1 mans 1 days work = $ x $ and 1 boys 1 days work = $ y $.
Then, 6$ x $ + 8$ y $ =$ \dfrac{1}{10} $and 26$ x $ + 48$ y $ =$ \dfrac{1}{2} $.
Solving these two equations, we get : $ x $ =$ \dfrac{1}{100} $and $ y $ =$ \dfrac{1}{200} $.
[15 men + 20 boy]s 1 days work =$ \left(\dfrac{15}{100} +\dfrac{20}{200} \right) $=$ \dfrac{1}{4} $.
$\therefore$ 15 men and 20 boys can do the work in 4 days.
3204.10 women can complete a work in 7 days and 10 children take 14 days to complete the work. How many days will 5 women and 10 children take to complete the work?
3
5
7
Cannot be determined
Explanation:
1 womans 1 days work =$ \dfrac{1}{70} $
1 childs 1 days work =$ \dfrac{1}{140} $
$\left(5 women + 10 children\right)$s days work =$ \left(\dfrac{5}{70} +\dfrac{10}{140} \right) $=$ \left(\dfrac{1}{14} +\dfrac{1}{14} \right) $=$ \dfrac{1}{7} $
$\therefore$ 5 women and 10 children will complete the work in 7 days.
3206.A can finish a work in 18 days and B can do the same work in 15 days. B worked for 10 days and left the job. In how many days, A alone can finish the remaining work?
5
5$ \dfrac{1}{2} $
6
8
Explanation:
Bs 10 days work =$ \left(\dfrac{1}{15} \times 10\right) $=$ \dfrac{2}{3} $.
Remaining work =$ \left(1 -\dfrac{2}{3} \right) $=$ \dfrac{1}{3} $.
Now,$ \dfrac{1}{18} $work is done by A in 1 day.
$\therefore$ $ \dfrac{1}{3} $work is done by A in$ \left(18\times\dfrac{1}{3}\right) $= 6 days.