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NEET - Physics Laws of Motion Test Yourself

23386.A rocket with a lift–off mass 3.5 × 104 kg is blasted upwards with an initial acceleration of 10 m/s2. Then the initial thrust of the blast is
1.75 × 105 N
3.5 × 105 N
7.0 × 105 N
14.0 × 105 N
23387.The upper half of an inclined plane of inclination θ is perfectly smooth while lower half is rough. A block starting from rest at the top of the plane will again come to rest at the bottom, if the coefficient of friction between the block and lower half of the plane is given by
μ = 1 / tan θ
μ = 2 / tan θ
μ = 2 tan θ
μ = tan θ
23388.A horizontal force of 10 N is necessary to just hold a block stationary against a wall. The coefficient of friction between the block and the wall is 0.2. The weight of the block is
stationary block on wall
2 N
20 N
50 N
100 N
23389.A block of mass m is placed on a smooth wedge of inclination θ. The whole system is accelerated horizontally, so that the block does not slip on the wedge. The force exerted by the wedge on the block (g is acceleration due to gravity) will be :
mg sin θ
mg
mg/cos θ
mg cos θ
23390.A roller is made by joining together two cones at their vertices O. It is kept on two rails AB and CD which are placed asymmetrically (see figure), with its axis perpendicular to CD and its centre O at the centre of line joining AB and CD (see figure). It is given a light push so that it starts rolling with its centre O moving parallel to CD in the direction shown. As it moves, the roller will tend to
roller made of two cones
Turn right
Go straight
Turn left and right alternately
Turn left
23391.Three blocks with masses m, 2m and 3m are connected by strings, as shown in the figure. After an upward force F is applied on block m, the masses move upward at constant speed v. What is the net force on the block of mass 2 m?
(g is the acceleration due to gravity)
Zero
2 mg
3 mg
6 mg
23392.To determine the coefficient of friction between a rough surface and a block, the surface is kept inclined at 45° and the block is released from rest. The block takes a time t in moving a distance d. The rough surface is then replaced by a smooth surface and the same experiment is repeated. The block now takes a time t/2 in moving down the same distance d. The coefficient of friction is
3/4
5/4
1/2
1/ 2
23393.A block is pushed momentarily on a horizontal surface with initial velocity ‘v’. If ‘μ’ is the coefficient of sliding friction between the block and surface, the block will come to rest after time (‘g’ = acceleration due to gravity)
v / μg
vg / μ
vμ / g
μg / v
23394.A light spring balance hangs from the hook of the other light spring balance and a block of mass M kg hangs from the former one. Then the true statement about the scale reading is
Both the scales read M / 2 kg each
Both the scales read M kg each
The scale of the lower one reads M kg and of the upper one zero
The reading of the two scales can be anything but the sum of the reading will be M kg
23395.The figure shows the position–time (x – t) graph of one–dimensional motion of a body of mass 0.4 kg. The magnitude of each impulse is position–time graph of a one dimensional body
0.2 Ns
0.4 Ns
0.8 Ns
1.6 Ns
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