4360.The total of the ages of Amar, Akbar and Anthony is 80 years. What was the total of their ages three years ago ?
71 years
72 years
74 years
77 years
Explanation:
Required sum = (80 – 3 x 3) years = (80 – 9) years = 71 years.
Required sum = (80 – 3 x 3) years = (80 – 9) years = 71 years.
4361.Two bus tickets from city A to B and three tickets from city A to C cost Rs. 77 but three tickets from city A to B and two tickets from city A to C cost Rs. 73. What are the fares for cities B and C from A ?
Rs. 4, Rs. 23
Rs. 13, Rs. 17
Rs. 15, Rs. 14
Rs. 17, Rs. 13
Explanation:
Let Rs. x be the fare of city B from city A and Rs. y be the fare of city C from city a.Then, 2x + 3y = 77 …(i) and3x + 2y = 73 …(ii)Multiplying (i) by 3 and (ii) by 2 and subtracting, we get: 5y = 85 or y = 17.Putting y = 17 in (i), we get: x = 13.
Let Rs. x be the fare of city B from city A and Rs. y be the fare of city C from city a.Then, 2x + 3y = 77 …(i) and3x + 2y = 73 …(ii)Multiplying (i) by 3 and (ii) by 2 and subtracting, we get: 5y = 85 or y = 17.Putting y = 17 in (i), we get: x = 13.
4362.An institute organised a fete and 1/5 of the girls and 1/8 of the boys participated in the same. What fraction of the total number of students took part in the fete ?
2/13
13/40
Data inadequate
None of these
Explanation:
Suppose ther are 18 students (10 girls, 8 boys).1/5 of 10=2 (girls).1/8 of 8=1 (boy).Total participation=2+1=3.Total students=10+8=18.
Answer = 3/18 = 1/6.
Answer cannot be determined until we have the Ratio of girls to boys.
Suppose ther are 18 students (10 girls, 8 boys).1/5 of 10=2 (girls).1/8 of 8=1 (boy).Total participation=2+1=3.Total students=10+8=18.
Answer = 3/18 = 1/6.
Answer cannot be determined until we have the Ratio of girls to boys.
4363.A number of friends decided to go on a picnic and planned to spend Rs. 96 on eatables. Four of them, however, did not turn up. As a consequence, the remaining ones had to contribute Rs. 4 each extra. The number of those who attended the picnic was
8
12
16
24
4364.A, B, C, D and E play a game of cards. A says to B, If you give me three cards, you will have as many as E has and if I give you three cards, you will have as many as D has. A and B together have 10 cards more than what D and E together have. If B has two cards more than what C has and the total number of cards be 133, how many cards does B have ?
22
23
25
35
Explanation:
Clearly, we have :B-3 = E …(i)B + 3 = D …(ii)A+B = D + E+10 …(iii)B = C + 2 …(iv)
A+B + C + D + E= 133 …(v)
From (i) and (ii), we have : 2 B = D + E …(vi)
From (iii) and (vi), we have : A = B + 10 …(vii)
Using (iv), (vi) and (vii) in (v), we get:
(B + 10) + B + (B – 2) + 2B = 133 5B = 125 B = 25.
Clearly, we have :B-3 = E …(i)B + 3 = D …(ii)A+B = D + E+10 …(iii)B = C + 2 …(iv)
A+B + C + D + E= 133 …(v)
From (i) and (ii), we have : 2 B = D + E …(vi)
From (iii) and (vi), we have : A = B + 10 …(vii)
Using (iv), (vi) and (vii) in (v), we get:
(B + 10) + B + (B – 2) + 2B = 133 5B = 125 B = 25.
4365.A pineapple costs Rs. 7 each. A watermelon costs Rs. 5 each. X spends Rs. 38 on these fruits. The number of pineapples purchased is
2
3
4
Data inadequate
4366.A woman says, “If you reverse my own age, the figures represent my husbands age. He is, of course, senior to me and the difference between our ages is one-eleventh of their sum.” The womans age is
23 years
34 years
45 years
None of these
Explanation:
Let x and y be the tens and units digits respectively of the numeral denoting the womans age.Then, womans age = (10X + y) years; husbands age = (10y + x) years.Therefore (10y + x)- (10X + y) = (1/11) (10y + x + 10x + y) (9y-9x) = (1/11)(11y + 11x) = (x + y) 10x = 8y x = (4/5)yClearly, y should be a single-digit multiple of 5, which is 5.
So, x = 4, y = 5.
Hence, womans age = 10x + y = 45 years.
Let x and y be the tens and units digits respectively of the numeral denoting the womans age.Then, womans age = (10X + y) years; husbands age = (10y + x) years.Therefore (10y + x)- (10X + y) = (1/11) (10y + x + 10x + y) (9y-9x) = (1/11)(11y + 11x) = (x + y) 10x = 8y x = (4/5)yClearly, y should be a single-digit multiple of 5, which is 5.
So, x = 4, y = 5.
Hence, womans age = 10x + y = 45 years.
4367.A girl counted in the following way on the fingers of her left hand : She started by calling the thumb 1, the index finger 2, middle finger 3, ring finger 4, little finger 5 and then reversed direction calling the ring finger 6, middle finger 7 and so on. She counted upto 1994. She ended counting on which finger ?
Thumb
Index finger
Middle finger
Ring finger
Explanation:
Clearly, while counting, the numbers associated to the thumb will be : 1, 9,17, 25,…..i.e. numbers of the form (8n + 1).Since 1994 = 249 x 8 + 2, so 1993 shall correspond to the thumb and 1994 to the index finger.
Clearly, while counting, the numbers associated to the thumb will be : 1, 9,17, 25,…..i.e. numbers of the form (8n + 1).Since 1994 = 249 x 8 + 2, so 1993 shall correspond to the thumb and 1994 to the index finger.
4368.A man has Rs. 480 in the denominations of one-rupee notes, five-rupee notes and ten-rupee notes. The number of notes of each denomination is equal. What is the total number of notes that he has ?
45
60
75
90
Explanation:
Let number of notes of each denomination be x.Then, x + 5x + 10x = 480 16x = 480 x = 30.Hence, total number of notes = 3x = 90.
Let number of notes of each denomination be x.Then, x + 5x + 10x = 480 16x = 480 x = 30.Hence, total number of notes = 3x = 90.
4369.What is the product of all the numbers in the dial of a telephone ?
1,58,480
1,59,450
1,59,480
None of these
Explanation:
Since one of the numbers on the dial of a telephone is zero, so the product of all the numbers on it is 0.
Since one of the numbers on the dial of a telephone is zero, so the product of all the numbers on it is 0.