It is being given that (232 + 1) is completely divisible by a whole number. Which of the following numbers is completely divisible by this number?
216+1
216-1
7x223
296+1
Explanation:
Let 232=x
Then, (232+1)=(x+1)
Let x+1 be completely divisible by natural number N, then
(296+1)=[(232)3+1]=(x3+1)
=(x+1)(x2-x+1), which is completely divisible by N, since (x+1) divisible by N
Let 232=x
Then, (232+1)=(x+1)
Let x+1 be completely divisible by natural number N, then
(296+1)=[(232)3+1]=(x3+1)
=(x+1)(x2-x+1), which is completely divisible by N, since (x+1) divisible by N