Reversing the digits of fathers age we get sons age. One year ago father was twice in age of that of his son? find their current ages?
40
38
32
37
Explanation:
Let fathers age = 10x + y
Sons age = 10y + x (As, it is got by reversing digits of fathers age)
At that point
(10x + y) - 1 = 2{(10y + x) - 1}
=> x = (19y - 1)/8
Let y = 3 then x = 7.
For any other y value, x value combined with y value doesnt give a realistic age (like fathers age 120 etc)
So, this has to be solution.Hence fathers age = 73.
Sons age = 37.