If m and n are whole numbers such that $m^n$ = 121, the value of $(m - 1) ^ (n + 1)$ is:
1
10
121
1000
Explanation:
We know that $11^2$ = 121.
Putting m = 11 and n = 2, we get:
$(m - 1)^(n + 1)$ = $(11 - 1) ^ (2 + 1)$ = $10^3$ = 1000.