Ravi has a bag full of 10 nestle and 5 Cadbury chocolates out of these, he draws two chocolates. what is the probability that he would get at least one nestle chocolates?
19/21
3/7
2/21
1/3
Explanation:
Selecting at least one nestle chocolate= (1 nestle & 1 Cadbury) or 2 nestle
So, probability of selecting 2 out of 15=[(10C1 $\times$ 5C1) +10C2]/ 15C2 = [ (10 $\times$ 5) + 45]/ 105 = 35/105 = 19/21.