Two cars P and Q start from a point at the same time in a straight line and their positions are represented by xP(t) = at + bt2 and xQ(t) = ft – t2. At what time do the cars have the same velocity?
$\dfrac{f – a}{2(1 + b)}$
$\dfrac{a – f}{1 + b}$
$\dfrac{a + f}{2(b – 1)}$
$\dfrac{a + f}{2(1 + b)}$
Explanation:
VP = VQ
a + 2bt = f – 2t
t = $\dfrac{f – a}{2(b + 1)}$
