Two rotating bodies A and B of masses m and 2m with moments of inertia IA and IB (IB > IA) have equal kinetic energy of rotation. If LA and LB be their angular momenta respectively, then
$L_A > L_B$
$L_A = \dfrac{L_B}{2}$
$L_A > 2L_B$
$L_B > L_A$
Explanation:
$KE_A = KE_B$
$\dfrac{1}{2}I_A \omega_A^2 = \dfrac{1}{2}I_B \omega_B^2$ ⇒ since $I_B > I_A \ so \ \omega_B > \omega_A$
$\dfrac{1}{2}L_A \omega_A = \dfrac{1}{2}L_B \omega_B$ ⇒ $L_B > L_A$