The temperature inside a refrigerator is t2 ºC and the room temperature is t1 ºC. The amount of heat delivered to the room for each joule of electrical energy consumed ideally will be
$\dfrac{t_1 + t_2}{t_1 + 273}$
$\dfrac{t_1}{t_1 – t_2}$
$\dfrac{t_1 + 273}{t_1 – t_2}$
$\dfrac{t_2 + 273}{t_1 – t_2}$
Explanation:
$\dfrac{Q_{more}}{W} = \dfrac{Q_{more}}{Q_{more} – Q_{less}} = \dfrac{T_{more}}{T_{more} – T_{less}} = \dfrac{t_1 + 273}{t_1 – t_2}$