The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15 and 18 is:
74
94
184
364
Explanation:
L.C.M. of 6, 9, 15 and 18 is 90.
Let required number be 90x + 4, which is multiple of 7.
Least value of k for which (90x + 4) is divisible by 7 is k = 4.
Hence, the required number = (90 $\times$ 4) + 4 = 364.