The solubility of AgCl (s) with solubility product 1.6 × 10–10 in 0.1 M NaCl solution would be
Zero
1.26 × 10–5 M
1.6 × 10–9 M
1.6 × 10–11 M
Explanation:
AgCl ⇋ Ag+ + Cl–
AgCl ⇋ Ag+ + Cl–
Ag+ is S
Cl– is 0.1
Ksp = [Ag+] [Cl–]
1.6 × 10–10 = S × 0.1
1.6 × 10–9 = S