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The solubility of AgCl (s) with solubility product 1.6 × 10–10 in 0.1 M NaCl solution would be

Zero
1.26 × 10–5 M
1.6 × 10–9 M
1.6 × 10–11 M
Explanation:
AgCl ⇋ Ag+ + Cl

Ag+ is S

Cl is 0.1

Ksp = [Ag+] [Cl]

1.6 × 10–10 = S × 0.1

1.6 × 10–9 = S

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