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If the sum of three consecutive even numbers is 44 more than the average of these numbers, then the largest of these numbers is?

20
24
22
None of these
Explanation:

Let the smallest of these number be x. The other two numbers are (x + 2) and (x + 4).

=> x + (x + 2) + (x + 4) = (X + (X+2) + (x+4)) / 3 + 44

=> 3x + 3 $\times$ (x + 2) + 3 $\times$ (x + 4) = x + (x + 2) + (x + 4) + 132

=> 9x + 18 = 3x + 138

=> 6x = 120

=> x = 20

Therefore, the largest number is 24.

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