A and B go cycling in the same direction with speeds of 6 km/hr. and 12 km/hr. A car from behind passes them in 9 and 10 seconds respectively. What is the speed of the car?
22 km/hr.
33 km/hr.
66 km/hr.
44 km/hr.
Explanation:
The relative speed of A and B is 6 km/hr. = 1.67 m/s
As the car passes A after 10s, the distance between A and B after 10s (i.e. at 11th second) is the distance covered by car in 1 second.
Therefore, at t = 11, d = 1.67 $\times$ 11
d = 18.33 m
v = d/t = 18.33/1 = 18.33m/s
v = 66 km/hr.