Easy Tutorial
For Competitive Exams

A father is three times as old as his son. After fifteen years the father will be twice as old as his son`s age at that time. Hence the father`s present age is

36
42
45
48
Explanation:

Let the son`s age be x, then father`s age 3x.

After 15 years:

Father`s age: 3x+15

Son`s age:x+15

Now the equation is:2(x+15) =3x+15

Solving we get x=15

Hence, father`s present is 45.

Share with Friends
Privacy Copyright Contact Us