Consider the reaction :
4NO2(g) + O2(g) ⟶ 2N2O5(g), ΔrH = –111 kJ.
If N2O5(s) is formed instead of N2O5(g) in the above reaction, the ΔrH value will be:
(given, ΔH of sublimation for N2O5 is 54 kJ mol–1)
–219 kJ
–165 kJ
+54 kJ
+219 kJ
Next Question
For a particular reversible reaction at temperature T, ΔH and ΔS were found to be both +ve. If Te is the temperature at equilibrium, the reaction would be spontaneous when