The number of hexagonal faces that are present in truncated octahedron is
14
12
10
8
Additional Questions
|
In a face–centered cubic lattice, a unit cell is shared equally by how many unit cells? |
Answer |
|
A compound is formed by elements A and B. This crystallizes in the cubic structure where A atoms are at the corners of the cube and B atoms are at the body centres. The simplest formula of the compound is |
Answer |
|
The crystal system of a compound with unit cell dimensions, a = 0.387, b = 0.387 and c = 0.504 nm and α = β = 90° and γ = 120° is |
Answer |
|
The radius ratio in CsCl is 0.93. The expected lattice structure is |
Answer |
|
The unit cell of a binary alloy composed of A and B metals, has a ccp structure with A atoms occupying the corners and B atoms occupying the centres of each face of the cube. If during the crystallization of this alloy, in the unit cell, two A atoms are missing, the overall composition per unit cell is |
Answer |
|
Which of the following is a molecular crystal? |
Answer |
|
To get n–type doped semiconductor, the impurity to be added to silicon should have the following number of valence electrons? |
Answer |
|
Three elements A, B and C crystalise into a cubic solid lattice. Atoms A occupy the corners, B occupies the cube centres and C occupies the edges. The formula of the compound is |
Answer |
|
Number of unit cells in 4 g of X (atomic mass = 40) which crystallize in bcc pattern is (NA= Avogadro number) |
Answer |
|
The number of octahedral void(s) per atom present in a cubic close–packed structure is |
Answer |