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Zn | Zn2+ (a = 0.1M) || Fe2+ (a = 0.01M) | Fe. The emf of the above cell is 0.2905 V. Equilibrium constant for the cell reaction is

100.32/0.0591
100.32/0.0295
100.26/0.0295
e0.32/0.295
Additional Questions

Calculate the reduction potential of a half–cell containing platinum electrode immersed in 2.0 M Fe2+ and 0.02 M Fe3+.

Given Eo
Fe3+/Fe2+
= 0.771 V.

Fe3+ + e → Fe2+

Answer

Consider the following four electrodes,

P = Cu2+ (0.0001 M) | Cu(s)

Q = Cu2+ (0.1 M) | Cu(s)

R = Cu2+ (0.01 M) | Cu(s)

S = Cu2+ (0.001 M) | Cu(s)

If the standard reduction potential of Cu2+/Cu is +0.34 V, the reduction potentials in volts of the above electrodes follow the order

Answer

Conductivity of 0.01 M NaCl solution is 0.00147 ohm–1cm–1. What happens to this conductivity if extra 100 ml of H2O will be added to the above solution?

Answer

Cr2O2–
7
+ I → I2 + Cr3+

EѲ
cell
= 0.79 V and EѲ of Cr2O2–
7
= 133 V. EѲ of I2 is

Answer

How many moles of Pt may be deposited on the cathode when 0.80 F of electricity is passed through a 1.0 M solution of Pt4+?

Answer

One ampere of current is passed for 9650 seconds through molten AlCl3. What is the weight in grams of Al deposited at cathode? (Atomic weight of Al = 27)

Answer

Molar ionic conductivities of a bivalent electrolyte are 57 and 73. The molar conductivity of the solution will be

Answer

One Faraday of electricity is passed through molten Al2O3,aqueous solution of CuSO4 and molten NaCl taken in three different electrolytic cells connected in series. The mole ratio of Al, Cu and Na deposited at the respective cathode is

Answer

Several blocks of magnesium are fixed to the bottom of a ship to

Answer

When a lead storage battery is discharged

Answer
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