What would happen when a solution of potassium chromate is treated with an excess of dilute nitric acid?
Cr3+ and Cr2O2–
7
7
Cr2O2–
7 and H2O are formed
7 and H2O are formed
Cr2O2–
4 is reduced to +7 state of Cr
4 is reduced to +7 state of Cr
Cr2O2–
4 is reduced to +3 state of Cr
4 is reduced to +3 state of Cr