Let [ε0] denote the dimensional formula of the permittivity of vacuum. If M = mass, L = length, T = time and A = electric current, then:
[ε0] = [M–1L–3T4A2]
[ε0] = [M–1L2T–1A–2]
[ε0] = [M–1L2T–1A]
[ε0] = [M–1L–3T2A]
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