Easy Tutorial
For Competitive Exams

Kinetic energy of a particle moving along the circle is $ax^2$. If R is the radius of the circle. The radial force on the particle is

$\dfrac{2ax^2}{R}$
$\left[\dfrac{1 + x^2}{R^2}\right]^{1/2}$
$2ax$
$\dfrac{2aR^2}{x}$
Share with Friends
Privacy Copyright Contact Us