The angle between the minute hand and the hour hand of a clock when the time is 4.20, is:
0$^\circ$
10$^\circ$
5$^\circ$
20$^\circ$
Explanation:
Angle traced by hour hand in$ \dfrac{13}{3} $hrs =$\left(\dfrac{360}{12}\times\dfrac{13}{3}\right)^\circ$= 130$^\circ$
Angle traced by min. hand in 20 min. =$ \left(\dfrac{360}{60} \times 20\right)^\circ $= 120$^\circ$.
$\therefore$ Required angle = (130 - 120)$^\circ$ = 10$^\circ$.