If P is the exerted by a gas and E is the K.E. per unit volume, then
P = $\dfrac{\text{E}}{3}$
P = $\dfrac{\text{E}}{3}$
P = $\dfrac{\text{2E}}{3}$
P = $\dfrac{3}{\text{2E}}$
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A gas at a pressure P0 is contained in a vessel. If the masses of all the molecules are halved and their velocities doubled, the resulting pressure P would be equal to