One pipe can fill a tank three times as fast as another pipe. If together the two pipes can fill the tank in 36 minutes, then the slower pipe alone will be able to fill the tank in:

For Competitive Exams

81 min.

108 min.

144 min.

192 min.

Explanation:

Let the slower pipe alone fill the tank in $ x $ minutes.

Then, faster pipe will fill it in$ \dfrac{x}{3} $minutes.

$\therefore \dfrac{1}{x} $+$ \dfrac{3}{x} $=$ \dfrac{1}{36} $

$\Rightarrow \dfrac{4}{x} $=$ \dfrac{1}{36} $

$\Rightarrow x $ = 144 min.

Next Question

Two pipes A and B can separately fill a cistern in 40 minutes and 30 minutes respectively. There is a third pipe in the bottom of the cistern to empty it. If all the three pipes are simultaneously opened, then the cistern is full in 20 minutes. In how much time, the third pipe alone can empty the cistern?

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