In how many ways can a group of 5 men and 2 women be made out of a total of 7 men and 3 women?
63
90
126
45
Explanation:
| Required number of ways = (7C5 x 3C2) = (7C2 x 3C1) =$ \left(\dfrac{7 \times 6}{2 \times 1} \times 3\right) $= 63. |