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Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.

4
7
9
13
Explanation:

Required number = H.C.F. of $\left(91 - 43\right)$, $\left(183 - 91\right)$ and $\left(183 - 43\right)$

     = H.C.F. of 48, 92 and 140 = 4.

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