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The L.C.M. of two numbers is 48. The numbers are in the ratio 2 : 3. Then sum of the number is:

28
32
40
64
Explanation:

Let the numbers be 2 x and 3 x .

Then, their L.C.M. = 6 x .

So, 6 x = 48 or x = 8.

$\therefore$ The numbers are 16 and 24.

Hence, required sum = $\left(16 + 24\right)$ = 40.

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