A can run 22.5 m while B runs 25 m. In a kilometre race B beats A by:
100 m
111$ \dfrac{1}{9} $m
25 m
50 m
Explanation:
When B runs 25 m, A runs$ \dfrac{45}{2} $m.
When B runs 1000 m, A runs$ \left(\dfrac{45}{2} \times\dfrac{1}{25} \times 1000\right) $m= 900 m.
$\therefore$ B beats A by 100 m.