Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be Rs. 3508, what was the amount invested in Scheme B?

Rs. 6400

Rs. 6500

Rs. 7200

Rs. 7500

Explanation:

Let the sum invested in Scheme A be Rs. $ x $ and that in Scheme B be Rs.13900 - x.

Then,$ \left(\dfrac{x \times 14 \times 2}{100} \right) $+$ \left(\dfrac{(13900 - x) \times 11 \times 2}{100} \right) $= 3508

$\Rightarrow$ 28$ x $ - 22$ x $ = 350800 - $\left(13900 \times 22\right)$

$\Rightarrow$ 6$ x $ = 45000

$\Rightarrow x $ = 7500.

So, sum invested in Scheme B = Rs. $\left(13900 - 7500\right)$ = Rs. 6400.