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A and B can together finish a work 30 days. They worked together for 20 days and then B left. After another 20 days, A finished the remaining work. In how many days A alone can finish the work?

40
50
54
60
Explanation:

$\left(A + B\right)$s 20 days work =$ \left(\dfrac{1}{30} \times 20\right) $=$ \dfrac{2}{3} $.

Remaining work =$ \left(1 -\dfrac{2}{3} \right) $=$ \dfrac{1}{3} $.

Now,$ \dfrac{1}{3} $work is done by A in 20 days.

Therefore, the whole work will be done by A in $\left(20 \times 3\right)$ = 60 days.

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