A and B together can do a piece of work in 30 days. A having worked for 16 days, B finishes the remaining work alone in 44 days. In how many days shall B finish the whole work alone?
30 days
40 days
60 days
70 days
Explanation:
Let As 1 days work = $ x $ and Bs 1 days work = $ y $.
Then, $ x $ + $ y $ =$ \dfrac{1}{30} $and 16$ x $ + 44$ y $ = 1.
Solving these two equations, we get: $ x $ =$ \dfrac{1}{60} $and $ y $ =$ \dfrac{1}{60} $
$\therefore$ Bs 1 days work =$ \dfrac{1}{60} $.
Hence, B alone shall finish the whole work in 60 days.