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There are 8 digits and 5 alphabets.In how many ways can you form an alphanumeric word using 3 digits and 2 alphabets?

43500
43200
54300
43100
Explanation:

Select 3 digits from 8 digits i. e.

8C3 ways

And also select 2 alphabets from 5 alphabets i.e.,

5C2 ways

Now to form a alphanumeric word of 5 characters we have to arrange the 5 selected digits.

So the answer is .

8C3 $\times$ 5C2 $\times$ 5! = 43200

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