If $\dfrac{1}{2(2x+3y)}+\dfrac{12}{7(3x-2y)}=\dfrac{1}{2} $ and $\dfrac{7}{2x+3y}+\dfrac{4}{3x-2y}=2 $ then values of x and y are respectively.
2, 1
1, 2
-1, -2
-2, 1
Explanation:
Substitute from option where x=2,y=1
Therefore 2,1
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