Easy Tutorial
For Competitive Exams

In a certain code word ACEG is written as 16 and DFGH is written as 25 then how can be written HIKM

36
41
40
39
Explanation:

A C E G

2+3+5+7=16

D F G H

4+6+7+8=25

H I K M

8+9+11+13=41

Share with Friends
Privacy Copyright Contact Us