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Find the average of first n natural numbers

$\dfrac{n(n+1)}{2}$
$\dfrac{n(n+1)(2n+1)}{2}$
$\dfrac{(n+1)}{2}$
n2
Explanation:

$Average=\dfrac{n((n+1)/2)}{n}$

$=\dfrac{n+1}{2}$

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