Find the average of first n natural numbers
$\dfrac{n(n+1)}{2}$
$\dfrac{n(n+1)(2n+1)}{2}$
$\dfrac{(n+1)}{2}$
n2
Explanation:
$Average=\dfrac{n((n+1)/2)}{n}$
$=\dfrac{n+1}{2}$
Find the average of first n natural numbers
$Average=\dfrac{n((n+1)/2)}{n}$
$=\dfrac{n+1}{2}$