Using the clay, Malar makes a cone, a hemisphere and a cylinder have equal bases and the heights of the cone and a cylinder are equal. They same as the common radius then find the ratio of their respective volumes
1:2:3
1:2: 4
1:2: 5
1:2: 6
Explanation:
volume of cone :volume of hemisphere :volume of cylinder
$\dfrac{1}{3}\pi r^{2}h:\dfrac{2}{3}\pi r^{3}:\pi r^{2}h$
put r=h then,
$\dfrac{1}{3}\pi r^{3}:\dfrac{2}{3}\pi r^{3}:\pi r^{3} $---->(1)
multiply (1) by 3 then,
$\dfrac{1}{3}\times 3 :\dfrac{2}{3}\times 3 : 1\times 3$
1:2:3
volume of cone :volume of hemisphere :volume of cylinder
$\dfrac{1}{3}\pi r^{2}h:\dfrac{2}{3}\pi r^{3}:\pi r^{2}h$
put r=h then,
$\dfrac{1}{3}\pi r^{3}:\dfrac{2}{3}\pi r^{3}:\pi r^{3} $---->(1)
multiply (1) by 3 then,
$\dfrac{1}{3}\times 3 :\dfrac{2}{3}\times 3 : 1\times 3$
1:2:3