The radii of two circular ends of a frustum shaped bucket are 15 cm and 8 cm. If its depth is 63 cm, find the capacity of the bucket in litres (Take $\pi=\dfrac{22}{7}$)
2.6994 litres
26.994 litres
269.94 litres
2699.4 litres
Explanation:
capacity of bucket=$\dfrac{1}{3}\pi h[R^{2}+r^{2}+Rr]$
=$\dfrac{1}{3}\times\frac{22}{7}\times 63[225+64+120]$
=$22\times 3\times 409$
=$26994cm^{3} [1 litre=1000c m^{3}]$
=26.994litre
capacity of bucket=$\dfrac{1}{3}\pi h[R^{2}+r^{2}+Rr]$
=$\dfrac{1}{3}\times\frac{22}{7}\times 63[225+64+120]$
=$22\times 3\times 409$
=$26994cm^{3} [1 litre=1000c m^{3}]$
=26.994litre