A function f:(-7,6) $\Rightarrow$ R is defined as follows 
what is the value of $\dfrac{4f(-3)-2f(4)}{f(-6)-4f(1)}$ ?
$\dfrac{2}{7}$
$\dfrac{7}{2}$
2
$\dfrac{1}{2}$
Explanation:
f(-3)=x+5=-3+5=2
f(4)=x-1=4-1=3
f(-6)=$x^{2}+2x+1$=36-12+1=25
f(1)=x+5=1+5=6
f(-3)=x+5=-3+5=2
f(4)=x-1=4-1=3
f(-6)=$x^{2}+2x+1$=36-12+1=25
f(1)=x+5=1+5=6
$\dfrac{(4\times 2) -(2\times 3)}{18-4(6)}$
=$\dfrac{8-6}{25-24}$
=2