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x3/2 : 9 = 16: $\sqrt{x}$. What is the value of x ?

$\pm$ 16
$\pm$ 3
$\pm$ 4
$\pm$ 12
Explanation:

$\dfrac{x^{\dfrac{3}{2}}}{9}=\dfrac{16}{x^{\dfrac{1}{2}}}$

$x^{\dfrac{3}{2}+\dfrac{1}{2}}=16\times9$

$x^{2}=16\times9$

$x=4\times3=12$

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