A person travels from P to Q at a speed of 40 km/hr and returns by increasing his speed by 50%. What is his average speed for both the trips ?
44 km/hour
46 km/hour
48 km/hour
50 km/hour
Explanation:
Speed while going = 40 km/hr
Speed while returning = 150% of 40 = 60 km/hr
Average speed =2xy/(x+y)
=2∗40∗60/(40+60)
=4800/100
=48Km/hr
Speed while going = 40 km/hr
Speed while returning = 150% of 40 = 60 km/hr
Average speed =2xy/(x+y)
=2∗40∗60/(40+60)
=4800/100
=48Km/hr