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Out of 7 consonants and 4 vowels, how many words of 3 consonants and 2 vowels can be formed?

210
1050
25200
21400
Explanation:
Number of ways of selecting (3 consonants out of 7) and (2 vowels out of 4) = (7C37C3*4C24C2)

= 210.



Number of groups, each having 3 consonants and 2 vowels = 210.



Each group contains 5 letters.



Number of ways of arranging 5 letters among themselves = 5! = 120



Required number of ways = (210 x 120) = 25200.
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