In particular language if A=0, B=1, C=2,........ , Y=24, Z=25 then what is the value of ONE+ONE (in the form of alphabets only)
BDAI
ABDI
DABI
CIDA
Explanation:
This problem is based on Base 26 rather than regular base 10 (decimal system) that we normally use. In base 10 there are 10 digits 0 to 9 exist. In base 26 there are 26 digits 0 to 25 exist. To convert any number into base 26, we have to divide the number with 26 and find the remainder.
Here, ONE + ONE =
E has value of 4. So E + E = 8 which is equal to I.
Now N + N = 13 + 13 = 26. But in base 26, there is no 26. So
$(26)_{10}=(10)_{26}$
So we put 0 and 1 carry over. But 0 in this system is A.
Now O + O + 1 = 14 + 14 + 1 = 29
Therefore,
$(29)_{10}=$(13)_{26}
But 1 = B and 3 = D in that system. So ONE + ONE = BDAI
This problem is based on Base 26 rather than regular base 10 (decimal system) that we normally use. In base 10 there are 10 digits 0 to 9 exist. In base 26 there are 26 digits 0 to 25 exist. To convert any number into base 26, we have to divide the number with 26 and find the remainder.
Here, ONE + ONE =
E has value of 4. So E + E = 8 which is equal to I.
Now N + N = 13 + 13 = 26. But in base 26, there is no 26. So
$(26)_{10}=(10)_{26}$
So we put 0 and 1 carry over. But 0 in this system is A.
Now O + O + 1 = 14 + 14 + 1 = 29
Therefore,
$(29)_{10}=$(13)_{26}
But 1 = B and 3 = D in that system. So ONE + ONE = BDAI