2 men and 4 boys can complete a work in 4 days. 5 men and 6 boys can complete the same work in 3 days. The work done by 2 boys is equal to the work of how many men?
4
5
6
7
Explanation:
(2m + 4b)’s one day’s work = $\\dfrac{1}{4}$
(5m + 6b)’s one day’s work = $\\dfrac{1}{3}
=> (8m + 16b)’s one day’s work = (15m + 18b) ’s one day’s work
=> 7 men’s work = 2 boy’s work
(2m + 4b)’s one day’s work = $\\dfrac{1}{4}$
(5m + 6b)’s one day’s work = $\\dfrac{1}{3}
=> (8m + 16b)’s one day’s work = (15m + 18b) ’s one day’s work
=> 7 men’s work = 2 boy’s work