There is enough provisions for 600 men in an army camp for 25 days. If there were 300 men less, how long will the provision last?
35 days
40 days
45 days
50 days
Explanation:
We have, M1D1 = M2D2
600*25= 300* D2
D2 = $\\dfrac{ 600*25}{300}$ = 50 days.
We have, M1D1 = M2D2
600*25= 300* D2
D2 = $\\dfrac{ 600*25}{300}$ = 50 days.