A, B, C, D and E play a game of cards. A says to B, If you give me three cards, you will have as many as E has and if I give you three cards, you will have as many as D has. A and B together have 10 cards more than what D and E together have. If B has two cards more than what C has and the total number of cards be 133, how many cards does B have ?
22
23
25
35
Explanation:
Clearly, we have :B-3 = E …(i)B + 3 = D …(ii)A+B = D + E+10 …(iii)B = C + 2 …(iv)
A+B + C + D + E= 133 …(v)
From (i) and (ii), we have : 2 B = D + E …(vi)
From (iii) and (vi), we have : A = B + 10 …(vii)
Using (iv), (vi) and (vii) in (v), we get:
(B + 10) + B + (B – 2) + 2B = 133 5B = 125 B = 25.
Clearly, we have :B-3 = E …(i)B + 3 = D …(ii)A+B = D + E+10 …(iii)B = C + 2 …(iv)
A+B + C + D + E= 133 …(v)
From (i) and (ii), we have : 2 B = D + E …(vi)
From (iii) and (vi), we have : A = B + 10 …(vii)
Using (iv), (vi) and (vii) in (v), we get:
(B + 10) + B + (B – 2) + 2B = 133 5B = 125 B = 25.