A student got twice as many sums wrong as he got right. If he attempted 48 sums in all, how many did he solve correctly ?
12
16
18
24
Explanation:
Suppose the boy got x sums right and 2x sums wrong.
Then, x + 2x = 48 3x = 48 x = 16.
Suppose the boy got x sums right and 2x sums wrong.
Then, x + 2x = 48 3x = 48 x = 16.